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Maths TNSB Mentoring
Class 10 Crash course
Algebra
Annual revision II
10.
TBQ - Determine the value of k
Question:
5
m.
Find
the values of \(k\), for which the quadratic equation \(kx^2 - (8k + 8)x + 241 = 0\) has real and equal roots.
Answer
:
\(k =\)
−16
\(-\frac{1}{16}\)
\(\frac{1}{16}\)
16
(
Note
: Select multiple answers if necessary.)
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