TBQ - Verify the given equation — task. Maths TNSB Mentoring, Class 10 Crash course.

If \(A =\)

(\begin{array}{l} 5 & 3 & 1 \\ 2 & 2 & - 8 \\ 1 & 0 & -6 \end{array})

, \(B =\)

(\begin{array}{l} 2 & 3 & 4 \\ 1 & 11 & 2 \\ -7 & 1 & - 1 \end{array})

and \(C =\)

(\begin{array}{l} 8 & 3 & 5 \\ 1 & - 2 & 3 \\ 2 & 4 & -3 \end{array})

then verify that \(A + (B + C) = (A + B) + C\).

Answer:

\(B+C\) \(=\)

(\begin{array}{l} i & i & i \\ i & i & i \\ i & i & i \end{array})

\(A+(B+C)\) \(=\)

(\begin{array}{l} i & i & i \\ i & i & i \\ i & i & i \end{array})

......(1)

\(A+B\) \(=\)

(\begin{array}{l} i & i & i \\ i & i & i \\ i & i & i \end{array})

\((A+B)+C\) \(=\)

(\begin{array}{l} i & i & i \\ i & i & i \\ i & i & i \end{array})

......(2)

Equation (1) Equation (II)

Hence, verified.

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