TBQ - Find the value of X and Y — task. Maths TNSB Mentoring, Class 10 Crash course.

Find \(X\) and \(Y\) if \(X + Y =\)

(\begin{array}{l} 9 & 0 \\ 3 & 3 \end{array})

and \(X - Y\) \(=\)

(\begin{array}{l} 1 & 0 \\ 0 & 2 \end{array})

Answer:

X = (\begin{array}{l} i & i \\ \frac{i}{i} & \frac{i}{i} \end{array})

Y = (\begin{array}{l} i & i \\ \frac{i}{i} & \frac{i}{i} \end{array})

Did you find an error?

9. TBQ - Find the value of X and Y