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Maths TNSB Mentoring
Class 10 Crash course
Algebra
Annual Revision IV
9.
TBQ - Solve the following
Question:
5
m.
Find \(x\), \(y\), and \(z\) from the simultaneous equations
\(\frac{1}{3x} + \frac{1}{2y} - \frac{1}{4z} = \frac{1}{4}\); \(\frac{1}{x} = \frac{1}{3y}\); \(\frac{1}{x} - \frac{1}{5y} + \frac{4}{z} = 2 \frac{2}{15}\)
Answer
:
\(x =\)
\(y =\)
\(z =\)
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