Answer variants:
2(ac+bd)
4(adbc)2>0
c2+d2
real and equal
no real root
real and unequal roots
4bcbc2=0
Δ=0
4bcbc2=0
a2+b2
4(adbc)2<0
b24ac>0
b24ac<0
Show that the equation \(x^2(a^2 + b^2) + 2x(ac + bd) + c^2 + d^2 = 0\) has no real roots. If \(ad = bc\), then verify that the roots are real and equal.
 
Answer:
 
Here, \(a =\)
, \(b =\)
, \(c =\)
 
\(\Delta = b^2 - 4ac =\)
 
Since \(\Delta =\)
, the given equation has
.
 
If \(ad = bc\), then \(\Delta =\)
.
 
Therefore,
if \(ad = bc\) and so the roots will be
.
 
Hence, we proved.