A school announces that for a certain competitions, the cash price will be distributed for all the participants equally as shown below.
 
Number of participants (\(x\)) \(2\) \(4\) \(6\) \(8\) \(10\)
Amount for each participant in \(₹\) (\(y\)) \(120\) \(60\) \(40\) \(30\) \(24\)
 
(i) Obtain the constant of variation.
 
(ii) Graph the above data and hence, Compute how much will each participant get if the number of participants are \(12\).
 
Answer:
 
From the given table, as number of participants(\(x\)) , the amount for each participant(\(y\)) . This kind of proportionality is called .
 
(i) The constant of variation is .
 
(ii) Let us plot the points \((2, 120)\), \((4, 60)\), \((6, 40)\), \((8, 30)\) and \((10, 24)\) in the graph and join them to get a free-hand smooth curve.
 
From the graph, we can see that the relation \(xy =\) forms a .
 
Each participant receives \(Rs.) when there are \(12\) participants.