TBQ - Find the sum — task. Maths TNSB Mentoring, Class 10 Crash course.

If \(A =\)

(\begin{array}{l} 4 & 7 & - 2 \\ \frac{1}{2} & \frac{3}{4} & \sqrt{2} \\ 1 & 9 & 4 \end{array})

, \(B =\)

(\begin{array}{l} - 7 & 4 & - 3 \\ \frac{1}{4} & \frac{7}{2} & 3 \\ 5 & - 6 & 9 \end{array})

, determine \(4A - 3B\).

Answer:

\(4A - 3B\) \(=\)

(\begin{array}{l} i & i & i \\ \frac{i}{i} & \frac{i}{i} & i \sqrt{i} - i \\ i & i & i \end{array})

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5. TBQ - Find the sum