Find the equation of the straight line joining the point of intersection of \(3x + y + 4 = 0\) and \(x - 5y - 20 = 0\) to the point of intersection of \(7x - 3y = -12\) and \(2y = x + 3\).
Answer:
The point of intersection of \(3x + y + 4 = 0\) and \(x - 5y - 20 = 0\) is .
The point of intersection of \(7x - 3y = -12\) and \(2y = x + 3\) is .
The required equation of the straight line is .