Derive the equation of the straight line through the intersection of lines \(7x + 3y = 10\), \(5x - 4y = 1\) and parallel to the line \(12x + 5y + 12 = 0\).
Answer:
The point of intersection of the equations \(7x + 3y = 10\) and \(5x - 4y = 1\) is .
The required line is parallel to \(12x + 5y + 12 = 0\) is of the form .
The equation of the straight line is .