Find the equation of a straight line through the point of intersection of the lines \(8x + 3y = 18\), \(4x + 5y = 9\) and bisecting the line segment joining the points \((5,-4)\) and \((-7,6)\).
 
Answer:
 
The point of intersection of the two lines is ii,i.
 
The midpoint of the points \((3,-2)\) and \((-9,6)\) is i,i.
 
The required equation of the straight line is ii+iii=0.