Construct a \(\triangle PQR\) in which \(PQ\)\( = 5 \ cm\), \(\angle R = 40^{\circ}\) and the median \(RG\) from \(R\) to \(PQ\) is \(4.4 \ cm\). Find the length of the altitude from \(R\) to \(PQ\).
\(Step-1:\) Draw a line segment \(PQ\) of length \(\ cm\).
\(Step-2:\) At \(P\), draw \(PE\) such that \(\angle QPE =\) \(^{\circ}\).
\(Step-3:\) At \(P\), draw \(PF\) such that \(\angle EPF =\) \(^{\circ}\).
\(Step-4:\) Draw the to \(PQ\), which intersects \(PF\) at \(O\) and \(PQ\) at \(G\).
\(Step-5:\) With \(O\) as centre and \(OP\) as radius draw .
\(Step-6:\) From \(G\) mark arcs of radius \(\ cm\) on the circle. Mark them as \(R\) and \(S\).
\(Step-7:\) Join \(PR\) and \(RQ\). Then \(\triangle\) is the required triangle.
\(Step-8:\) From \(R\) draw a line \(RN\) to \(LQ\). \(LQ\) meets \(RN\) at \(M\).
\(Step-9:\) The length of the altitude is \(RM =\) \(\ cm\).