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Maths TNSB Mentoring
Class 10 Crash course
Geometry
Annual Revision III
1.
TBQ - Find the ratio of the areas
Question:
1
m.
In the given figure, \(ST \parallel QR\), \(PS = 5\) \(cm\) and \(SQ = 4 \ cm\). Then the ratio of the area of \(\triangle PQR\) to the area of \(\triangle PST\) is:
81:25
81:18
81:27
81:16
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