TBQ - Evaluate the value of n — task. Maths TNSB Mentoring, Class 10 Crash course.

If \(1 + 2 + 3 + … + n = 435\), then find \(n\).

Answer:

The sum of first \(n\) natural numbers \(=\)

\frac{i (i + i)}{i}

The value of \(n\) \(=\)

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6. TBQ - Evaluate the value of n