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Maths TNSB Mentoring
Class 10 Crash course
Numbers and Sequences
Annual Revision II
4.
TBQ - Find the value of x
Question:
2
m.
Find \(y\) so that \(y + 2\), \(y + 3\) and \(y + 5\) are consecutive terms of a geometric progression.
Answer
:
Which among the following is true for geometric progression?
t
3
t
1
=
t
3
t
2
t
2
t
1
=
t
3
t
2
t
1
t
2
=
t
2
t
3
t
2
t
3
=
t
1
t
2
The value of \(y\) is:
0
−1
−1
1
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