Find the value of:
 
62+72+82+...+172
 
Answer:
 
We know that, the sum of the squares of first \(n\) natural numbers \(=\) ii+iii+ii.
 
62+72+82+...+172 \(=\) \((1^2 + 2^2 + 3^2 + ... 17^2)\) 12+22+32+42+52
 
\(=\) \(-\)
 
\(=\)