Answer variants:
32x28
\(4x^2 + 8x + 3\)
\(4x^2\)
\(\frac{3 - x}{3} - 1\)
42x28
\(x^2 - 6\)
\(\frac{9 - x}{3}\)
\(x^2 - 12x + 36\)
\(x - 1\)
Using the functions \(f\) and \(g\) given below, find \(f \circ g\) and \(g \circ f\). Verify whether \(f \circ g = g \circ f\).
 
\(f(x) = \frac{4}{x}\), \(g(x) = 2x^2 - 8\)
 
\(f \circ g\) \(=\)
 
\(g \circ f\) \(=\)
 
So, .