If \(f(x) = 2x + 3\), \(g(x) = 1 - 2x\) and \(h(x) = 3x\). Check that \(f \circ (g \circ h) = (f \circ g) \circ h\).
Proof:
\(f \circ g(x) =\)
\((f \circ g) \circ h =\)
\(g \circ h(x) =\)
\(f \circ (g \circ h) =\)
Thus, .
Hence proved.
Answer variants:
\(f \circ (g \circ h) = (f \circ g) \circ h\)
\(1 - 6x\)