If \(A\), \(B\), \(C\) are any three events such that the probability of \(B\) is twice as that of probability of \(A\) and probability of \(C\) is thrice as that of probability of \(A\) and if \(P(A \cap B) = \frac{1}{6}\), \(P(B \cap C) = \frac{1}{4}\), \(P(A \cap C) = \frac{1}{8}\), \(P(A \cup B \cup C) = \frac{9}{10}\), \(P(A \cap B \cap C) = \frac{1}{14}\), then estimate \(P(A)\), \(P(B)\) and \(P(C)\)?
Answer:
\(P(A) =\)
\(P(B) =\)
\(P(C) =\)
[Note: Enter numerator and denominator in simplified form.]