Show that \(cot^2 \ C - cos^2 \ C = cot^2 \ C \ cos^2 \ C\)
 
Proof:
Answer variants:
\(cot^{2} \ C\)
\(cos^{2} \ C\)
\(tan^{2} \ C\)
\(sin^{2} \ C\)
LHS=cot2Ccos2C=cot2Ccos2Ci×i=cot2Ci×sin2C=cot2C1sin2C=cot2Ci