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Subjects
Maths TNSB Mentoring
Class 10 Crash course
Trigonometry
Annual Revision I
6.
PYQ - Prove the following II
Question:
2
m.
Show that
\(cot^2 \ C - cos^2 \ C = cot^2 \ C \ cos^2 \ C\)
Proof:
Answer variants:
\(cot^{2} \ C\)
\(cos^{2} \ C\)
\(tan^{2} \ C\)
\(sin^{2} \ C\)
LHS
=
cot
2
C
−
cos
2
C
=
cot
2
C
−
cos
2
C
i
×
i
=
cot
2
C
−
i
×
sin
2
C
=
cot
2
C
1
−
sin
2
C
=
cot
2
C
i
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