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Maths TNSB Mentoring
Class 10 Crash course
Trigonometry
Annual Revision III
1.
PYQ - Find the appropriate equation
Question:
1
m.
If \(x = a tan V\) and \(y = b sec V\) then
\(\frac{y^2}{b^2} - \frac{x^2}{a^2} = 0\)
\(\frac{x^2}{a^2} - \frac{y^2}{b^2} = 0\)
\(\frac{x^2}{a^2} - \frac{y^2}{b^2} = 1\)
\(\frac{y^2}{b^2} - \frac{x^2}{a^2} = 1\)
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