TBQ - Verify the following — task. Maths TNSB Mentoring, Class 10 Crash course.

Chech whether \(1 + \frac{tan^2 \ β}{1 + sec \ β} = sec \ β\)

Proof:

Answer variants:

\(cot^{2} \ β - 1\)

\(cosec \ β\)

\(sec \ β\)

\(cosec^{2} \ β - 1\)

\(sec^{2} \ β - 1\)

\begin{array}{l} LHS = 1 + \frac{\tan^{2} β}{1 + \sec β} \\ = 1 + \frac{i}{1 + \sec β} \\ = 1 + \frac{(\sec β + 1) (\sec β - 1)}{1 + \sec β} \\ = 1 + i - 1 \\ = \sec β \end{array}

Did you find an error?

5. TBQ - Verify the following