Prove that \(tan^4 \ q + tan^2 \ q\) \(=\) \(sec^4 \ q - sec^2 \ q\).
 
Proof:
 
\(LHS =\) \(tan^4 \ q + tan^2 \ q\)
 
\(=\)
 
\(=\)
----(1)
 
\(RHS =\) \(sec^4 \ q - sec^2 \ q\)
 
\(=\)
 
\(=\)
----(2)
 
From equations (\(1\)) and (\(2\)), we can see that \(LHS = RHS\).
 
Therefore, \(tan^4 \ q + tan^2 \ q\) \(=\) \(sec^4 \ q - sec^2 \ q\).
 
Hence, we proved.
Answer variants:
tan2qtan2q+1
sec2qsec2q1
tan2qsec2q
sec2qtan2q