Establish that \(\frac{sin \ X}{1 + cos \ X}\) \(=\) \(\frac{1 - cos \ X}{sin \ X}\)
 
Proof:
 
\(LHS =\) \(\frac{sin \ X}{1 + cos \ X}\)
 
\(=\)
 
\(=\)
 
\(=\)
 
\(=\)
 
\(= RHS\)
 
Hence, we proved.
Answer variants:
sinX(1cosX)12cos2X
sinX1+cosX×1cosX1cosX
sinX(1cosX)sin2X
1cosXsinX