TBQ - Prove the following II — task. Maths TNSB Mentoring, Class 10 Crash course.

Prove that

\sqrt{\frac{1 + \sin y}{1 - \sin y}} = \sec y + \tan y

Proof:

LHS \(=\)

\(=\)

\(=\) RHS

Hence, we proved.

Answer variants:

\frac{1 + \sin y}{\cos y}

\sqrt{\frac{{(1 + \sin y)}^{2}}{\cos^{2} y}}

\sqrt{\frac{1 + \sin y}{1 - \sin y} \times \frac{1 + \sin y}{1 + \sin y}}

\sec y + \tan y

\sqrt{\frac{1 + \sin y}{1 - \sin y}}

\sqrt{\frac{{(1 + \sin y)}^{2}}{1 - \sin^{2} y}}

\frac{1}{\cos y} + \frac{\sin y}{\cos y}

\sqrt{\frac{{(1 + \sin y)}^{2}}{1^{2} - \sin^{2} y}}

Did you find an error?

5. TBQ - Prove the following II