Answer variants:
9αβ+3(α+β)1
α2+β222αβ3αβ
α2+β22+2αβ3αβ
9αβ3(α+β)+1
α+βαβ
α+βαβ2
Write the following expression in terms of \(\alpha + \beta\) and \(\alpha \beta\).
 
\(\frac{\alpha}{3 \beta} + \frac{\beta}{3 \alpha} =\)