Determine: a216a38×2a23a22a2+9a+4÷3a211a4a2+2a+4 \(=\)
 
Answer variants:
\(\frac{a+1}{a-1}\)
\(\frac{3a+5}{3a-5}\)
\(\frac{1}{3a+1}\)
\(\frac{5a-6}{5+6a}\)