Answer variants:
28x+14y+3=0
28x+14y3=0
28x14y3=0
28x14y+3=0
Find the equation of the straight line through the intersection of the lines 7x2y+3=0 and 7x+6y+4=0 and perpendicular to the line 8x+4y+6=0.
 
Answer:
 
The equation of the straight line is
.