Login
Home
TOP
Send feedback
Login
Subjects
Maths TNSB Mentoring
Class 10
Coordinate Geometry
General Form of Straight Line II
2.
Five mark exercise problem IV
Question:
5
m.
\(A(-3,0)\), \(B(10,-2)\) and \(C(12,3)\) are the vertices of \(\triangle ABC\). Find the equation of the altitude through \(A\) and \(B\).
Answer
:
The
equation
of the altitude of \(AD\) is
\(2x - 5y + 6 = 0\)
\(2x + 5y + 6 = 0\)
\(2x + 5y - 6 = 0\)
\(2x - 5y - 6 = 0\)
.
The
equation
of the altitude of \(BE\) is
\(5x + y - 48 = 0\)
\(5x - y - 48 = 0\)
\(5x + y + 48 = 0\)
\(5x - y + 48 = 0\)
.
Login
or
Fast registration
Previous task
Exit to the topic
Next task
Send feedback
Did you find an error?
Send it to us!
