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Maths TNSB Mentoring
Class 10
Coordinate Geometry
Straight Line and Slope
7.
TBQ - Equation of the median and altitude
Question:
5
m.
Find the
equation
of the
median
and
altitude
of \(\triangle ABC\) through \(A\), where the vertices are \(A(6,2)\), \(B(-5,-1)\) and \(C(1,9)\).
The
equation
of the
median
of \(\triangle ABC\) is
\(x - 4y - 14 = 0\)
\(x + 4y + 14 = 0\)
\(x - 4y + 14 = 0\)
\(x + 4y - 14 = 0\)
.
The
equation
of the
altitude
of \(\triangle ABC\) is
\(3x + 5y - 28 = 0\)
\(3x + 5y + 28 = 0\)
\(3x - 5y - 28 = 0\)
\(3x - 5y + 28 = 0\)
.
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