Construct a triangle similar to a given triangle \(LMN\) with its sides equal to \(\frac{4}{5}\) of the corresponding sides of the triangle \(LMN\) (scale factor \(\frac{4}{5} < 1\))
Arrange the steps of construction in a correct order:
\(Step-1\) :
\(Step-2\) :
\(Step-3\) :
\(Step-4\) :
\(Step-5\) :
Then, \(L'MN'\) is the required triangle, each of whose side is four - fifth of the corresponding sides of \(\triangle LMN\).
Answer variants:
Construct a triangle \(LMN\) with any measurement.
Locate \(5\) (the greater of \(4\) and \(5\) in \(\frac{4}{5}\)) points. \(Q_1\), \(Q_2\), \(Q_3\), \(Q_4\) and \(Q_5\) on \(MX\) so that \(MQ_1 = Q_1Q_2 = Q_2Q_3 = Q_3Q_4 = Q_4Q_5\)
Join \(Q_5N\) and draw a line through \(Q_4\) (the fourth point, \(4\) being smaller of \(4\) and \(5\) in \(\frac{4}{5}\)) parallel to \(Q_5N\) to intersect \(QN\) at \(N'\).
Draw a line through \(N'\) parallel to the line \(LN\) to intersect \(ML\) at \(L''\).
Draw a ray \(MX\), making an acute angle with \(MN\) on the side opposite to vertex \(L\).