Consider the function \(f(p)\), \(g(p)\), \(h(p)\) as given below. Verify that \((f \circ g) \circ h = f \circ (g \circ h)\) in the below case.
 
\(f(p) = p - 1\), \(g(p) = 3p + 1\) and \(h(p) = p^2\)
 
Proof:
 
\(f \circ g\) \(=\) ii
 
\((f \circ g) \circ h\) \(=\) iii - - - - - - - (I)
 
\(g \circ h\) \(=\) iii+i
 
\(f \circ (g \circ h)\) \(=\) iii - - - - - - - (II)
 
Equation (I) Equation (II)
 
Hence, proved.