Consider the function \(f(p)\), \(g(p)\), \(h(p)\) as given below. Verify that \((f \circ g) \circ h = f \circ (g \circ h)\) in the below case.
\(f(p) = p - 1\), \(g(p) = 3p + 1\) and \(h(p) = p^2\)
Proof:
\(f \circ g\) \(=\)
\((f \circ g) \circ h\) \(=\) - - - - - - - (I)
\(g \circ h\) \(=\)
\(f \circ (g \circ h)\) \(=\) - - - - - - - (II)
Equation (I) Equation (II)
Hence, proved.