If \(P(A) = \frac{4}{9}\), \(P(B) = \frac{4}{9}\) and \(P(A \cap B) = \frac{1}{6}\), then find (i) \(P(A \text{ or }B)\) (ii) \(P(\text{not } A \text{ and not }B)\).
Answer:
(i) \(P(A \text{ or }B)\) \(=\)
(ii) \(P(\text{not } A \text{ and not }B)\) \(=\)
[Note: Enter the fractional values reduced to their lowest forms.]