Calculate the correct answer below:
 
If in figure, \(R_{1}\) \(=\) \(5\) Ω, \(R_{2}\) \(=\) \(10\) Ω, \(R_{3}\) \(=\) \(1\) Ω, \(R_{4}\) \(=\) \(20\) Ω, \(R_{5}\) \(=\) \(20\) Ω, and a \(12\ V\) battery is connected to the arrangement.
  
Calculate
a. the total resistance in the circuit, and
b. the total current flowing in the circuit.
 
series and parallel.png
Circuit diagram
 
Suppose we replace the parallel resistors \(R_{1}\) and \(R_{2}\) by an equivalent resistor of resistance, \(R'\), similarly we replace the parallel resistors \(R_{3}\), \(R_{4}\) and \(R_{5}\) by an equivalent single resistor of resistance \(R"\). Then,
 
1R=iR=iΩ
 
Similarly,
 
1R=iR=iΩ
 
Thus, the total resistance is Ω
 
By Ohm's law, the current formula is
 
I=ii
 
The current flowing in the circuit is \(A\).
 
[Note: Enter the answer up to three decimal places by rounding off the value]