TBQ - Joule's law of heating — task. Physics CBSE Live product, Class 10 (2026-27).

Solve the problem given below:

162 \(J\) of heat are produced each second in a 2

Ω

resistance. Find the potential difference across the resistor.

The current through the resistor is \(A\)

The potential difference is \(V\)

[Note: Enter the answer as a whole number.]

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7. TBQ - Joule's law of heating