Find the correct value below:
A battery of \(6\ V\) is connected in series with resistors of \(2\ Ω\), \(4\ Ω\), \(8\ Ω\), and \(11\ Ω\), respectively in a circuit. How much current would flow through the \(11\ Ω\) resistor?
The equivalent resistance is given as
On substituting the known values, we get \(R\ =\) \(Ω\)
Using Ohm's law, we get
The current flowing across the \(11\ Ω\) resistor is \(A\).
[Note: Enter the answer in two decimal place]