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Physics CBSE Live product
Class 10
Electricity
Annual Revision I - Electriicity
5.
PYQ - Calculate the potential difference
Question:
2
m.
Apply Ohm’s law to calculate the voltage across the \(\ 3 \Omega\) resistor in the circuit once the key is closed.
Total resistance
of the circuit is
\(6\ \Omega\)
\(0.5\ \Omega\)
\(3\ \Omega\)
\(9\ \Omega\)
The formula to calculate the
potential difference
is
\(V\ =\ \frac{R}{I}\)
\(V\ =\ \frac{I}{R}\)
\(V\ =\ I \times R\)
\(V\ =\ I\)
The
potential difference
across \(3\ \Omega\) is
\(0.33\ V\)
\(3\ V\)
\(1\ V\)
\(0.66\ V\)
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