Solve the given problem:
 
How much energy is given to each coulomb of charge passing through a 19 \(V\) battery?
 
\(V\) \(=\) 19 \(V\)
 
\(q\) \(=\) 1 \(C\)
 
The formula is
 
W=i×i
 
On substituting the known values, we get energy passing through a \(19\ V\) battery as  \(J\)