TBQ - Absolute refractive index — task. Physics CBSE Live product, Class 10.

Answer the following question:

The absolute refractive index of diamond is approximately \(2.4\), while the absolute refractive index of glass is around \(1.5\). Calculate the refractive index of diamond with respect to glass.

Let us consider,

\(n_{dg}\) - Refractive index of diamond with respect to glass

\(n_g\) - Absolute refractive index of glass

\(n_d\) - Absolute refractive index of diamond

Then, the formula to calculate \(v\) is,

\(n_{dg}\ =\ \frac{n_d}{n_g}\)
\(n_{dg}\ =\ {n_d} \times {n_g}\)
\(n_{dg}\ =\ {n_g} \times {n_d}\)
\(n_{dg}\ =\ \frac{n_g}{n_d}\)

Speed of light in the glass (\(v\)) \(=\) \(\times 10^8\ ms^{-1}\)

Important!

Note: Enter your answers with no decimal digits.

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7. TBQ - Absolute refractive index

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