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Physics CBSE Live product
Class 9 (2025-26)
Motion
Annual Revision IV - Motion
7.
Finding distance of a stone
Question:
2
m.
Solve the given problem:
How far a stone shall free fall in \(8\ second\) released from rest? (\(g\ =\ 9.8 \ ms^{-2})\)
313.6
\(92.8\)
\(18.6\)
\(36.4\)
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