Prove the given trigonometric equation — task. Maths CBSE Homework Assignments, Class 10.

Answer variants:

\frac{\sin A (1 - \cos A)}{1 - \cos^{2} A}

\frac{\sin A (1 - \cos A)}{(1 + \cos A) (1 - \cos A)}

\frac{\sin A (1 - \cos A)}{\sin^{2} A}

\frac{\sin A (1 + \cos A)}{1 - \cos^{2} A}

\frac{\sin A}{1 + \cos A} \times \frac{1 + \cos A}{1 + \cos A}

\frac{\sin A}{1 + \cos A} \times \frac{1 - \cos A}{1 - \cos A}

Prove that

\frac{\sin A}{1 + \cos A}

\(=\)

\frac{1 - \cos A}{\sin A}

Proof:

LHS \(=\)

\frac{\sin A}{1 + \cos A}

\(=\)

\frac{1 - \cos A}{\sin A}

\(=\) RHS

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1. Prove the given trigonometric equation