Prove the given trigonometric equation — task. Maths CBSE Homework Assignments, Class 10.

Answer variants:

\frac{\sin x ((\sin^{2} x + \cos^{2} x) + 2 \sin^{2} x)}{\cos x (2 \cos^{2} x + (\sin^{2} x + \cos^{2} x))}

\frac{\sin x (1 + 2 \sin^{2} x)}{\cos x (2 \cos^{2} x + 1)}

\frac{\sin x ((\sin^{2} x + \cos^{2} x) - 2 \sin^{2} x)}{\cos x (2 \cos^{2} x - (\sin^{2} x + \cos^{2} x))}

\frac{\tan x (\cos^{2} x - \sin^{2} x)}{(\cos^{2} x - \sin^{2} x)}

\frac{\sin x (\sin^{2} x + \cos^{2} x - 2 \sin^{2} x)}{\cos x (2 \cos^{2} x - \sin^{2} x - \cos^{2} x)}

\frac{\sin x (1 - 2 \sin^{2} x)}{\cos x (2 \cos^{2} x - 1)}

Show that

\frac{\sin x - 2 \sin^{3} x}{2 \cos^{3} x - \cos x}

\(=\)

\tan x

Proof:

LHS \(=\)

\frac{\sin x - 2 \sin^{3} x}{2 \cos^{3} x - \cos x}

\(=\)

\tan x

\(=\) RHS

Did you find an error?

1. Prove the given trigonometric equation