Explain the given trigonometric equation by matching correct options — task. Maths CBSE Homework Assignments, Class 10.

Answer variants:

\frac{\cos A (\frac{6}{\sin A} - 1)}{\cos A (\frac{6}{\sin A} + 1)}

\frac{(\frac{6}{\sin A} - 1)}{(\frac{6}{\sin A} + 1)}

\frac{(6 \times \frac{1}{\cos A} - 1)}{(6 \times \frac{1}{\cos A} + 1)}

\frac{6 (\frac{\cos A}{\sin A}) - \cos A}{6 (\frac{\cos A}{\sin A}) + \cos A}

\frac{(6 \times \frac{1}{\sin A} - 1)}{(6 \times \frac{1}{\sin A} + 1)}

\frac{6 (\frac{\sin A}{\cos A}) - \cos A}{6 (\frac{\sin A}{\cos A}) + \cos A}

Prove that

\frac{6 \cot A - \cos A}{6 \cot A + \cos A}

\(=\)

\frac{6 cosec A - 1}{6 cosec A + 1}

Proof:

LHS \(=\)

\frac{6 \cot A - \cos A}{6 \cot A + \cos A}

\(=\)

\frac{6 cosec A - 1}{6 cosec A + 1}

\(=\) RHS

Did you find an error?

2. Explain the given trigonometric equation by matching correct options