Prove that \(\frac{1 + \sec θ}{\sec θ} = \frac{\sin^2 θ}{1 - \cos θ}\).
 
Proof:
 
LHS=1+secθsecθ=1iθ+iθiθ=iθ+1(1)RHS=sin2θ1cosθ=1i2θ1cosθ=(1iθ)(1+iθ)1cosθ=1+iθ(II)
 
 
Therefore, from \((I)\) and \((II)\), we get:
 
LHS \(=\) RHS
 
Hence proved.