If \(cosec \  B+ cot \ B = q\), then prove that \(cos  B= \frac{q^2 - 1}{q^2 + 1}\).
 
Proof:
 
LHScosecB+cotB=qq=1iB+cosBiBsquaringonbothsides,weget:q2=1+iB1−iBq2(1−iB)=1+iB1+iB=q2−q2iBiB(1+q2)=q2−1
 
By simplifying this we get, 
 
\(cos B =\frac{q^2 - 1}{q^2+1}\)