Show that\(\frac{cos \theta}{1+sin \theta}=\frac{1-sin \theta}{cos \theta}\)
Proof:
Consider, \(\frac{cos \theta}{1+sin \theta} = \)
\(=\)
\(=\)
By using identity,
\(=\)
\(=\)
\(LHS = RHS\)
Hence proved
Answer variants:
\(sin^2\ \theta + cos^2\ \theta = 1\)
\(sin^2\ \theta - cos^2\ \theta =1\)