Find the zeroes \(\alpha\) and \(\beta\) of the polynomial \(f(x)=x^2-9x-k(k+9)\), and hence, using the sum and product of the zeroes, find the value of \(\frac{1}{\alpha^2}+\frac{1}{\beta^2}\).
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Answer:
The value of\(\frac{1}{\alpha^2}+\frac{1}{\beta^2}\) =
