Find the required length — task. Maths CBSE Live product, Class 10.

Answer variants:

12 \sqrt{2}

\frac{QR}{12 \sqrt{2}}

12

\frac{1}{\sqrt{2}}

\(QR\) and \(SR\) are two tangents from the point \(R\). If \(\angle QRP\) \(=\)

45 °

and \(PR\) \(=\)

12 \sqrt{2}

\(cm\), then find the length of \(QR\).

Answer:

In the triangle \(PQR\), \(\cos\)\(R\) \(=\)

The length of \(QR\) \(=\)

\(cm\)

Did you find an error?

2. Find the required length