Find the zeroes of the polynomial \(r^2 + \frac{1}{3}r - \frac{2}{9}\), and verify the relation between the coefficients and the zeroes of the polynomial.
Answer:
The zeroes are and .
Sum of the zeroes \(=\)
Product of the zeroes \(=\)
Answer variants:
\( r = -\frac{3}{18}\)
\( r = \frac{-2}{3}\)
\( r = \frac{1}{3}\)
\(r = \frac{4}{18}\)