Answer variants:
6x27x1=0
x2+23x+76=0
6x2+7x+1=0
x223x76=0
x223x+76=0
6x27x+1=0
If \(\alpha\) and \(\beta\) are the roots of the equation x2+7x+6=0, then find the quadratic equation whose roots are:
 
(i) 1α and 1β
 
The equation is
.
 
(ii) \((3\alpha - 1)\) and \((3\beta - 1)\)
 
The equation is
.