Prove that \(13+\sqrt{2}\) is irrational.
Proof:
Let us consider \(13+\sqrt{2}\) is .
Therefore, \(13+\sqrt{2}\) can be expressed as \(\frac{p}{q}\), where \(p\) and \(q\) are any two integers such that \(q\neq 0\)
\(13+\sqrt{2}=\frac{p}{q}\)
Hence, \(\sqrt{2}=\frac{q}{p}-\)
\(\frac{p}{q}-13\) is as \(p\) and \(q\) are .
Therefore, \(\sqrt{2}\) is which contradicts the fact that \(\sqrt{2}\) is .
Hence, \(13+\sqrt{2}\) is .