The shadow of a tower standing on a level plane is found to be \(50 \ m\) longer when Sun's elevation is \(30^{\circ}\) than when it is \(60^{\circ}\). Find the height of the tower.
Answer:
Let \(SQ\) denote the height of the tower.
Here, \(SQ = h\), \(\angle SPQ = 30^{\circ}\), \(\angle SRQ = 60^{\circ}\), \(PR = 50 \ m\) and \(RQ = x\).
\(x=\)
Height of the tower \(=\)